Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 6 } ~ \text{ and } ~ \color{red}{ c = -40 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 6 } $ and multiply to $ \color{red}{ -40 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = -40 }$.
| PRODUCT = -40 | |
| -1 40 | 1 -40 |
| -2 20 | 2 -20 |
| -4 10 | 4 -10 |
| -5 8 | 5 -8 |
Step 3: Find out which pair sums up to $\color{blue}{ b = 6 }$
| PRODUCT = -40 and SUM = 6 | |
| -1 40 | 1 -40 |
| -2 20 | 2 -20 |
| -4 10 | 4 -10 |
| -5 8 | 5 -8 |
Step 4: Put -4 and 10 into placeholders to get factored form.
$$ \begin{aligned} k^{2}+6k-40 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ k^{2}+6k-40 & = (x -4)(x + 10) \end{aligned} $$