Question
Factor polynomial $$ b^{3}-64a^{3} $$
Answer
$$ b^{3}-64a^{3} = (b-4a)(b^{2}+4ab+16a^{2}) $$
Explanation
To factor $ b^{3}-64a^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = b $ and $ II = 4a $ , we have:
$$ b^{3}-64a^{3} = ( b-4a ) ( b^{2}+4ab+16a^{2} ) $$This page was created using
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