Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = -1 } ~ \text{ and } ~ \color{red}{ c = -992 }$$Now we must discover two numbers that sum up to $ \color{blue}{ -1 } $ and multiply to $ \color{red}{ -992 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = -992 }$.
| PRODUCT = -992 | |
| -1 992 | 1 -992 |
| -2 496 | 2 -496 |
| -4 248 | 4 -248 |
| -8 124 | 8 -124 |
| -16 62 | 16 -62 |
| -31 32 | 31 -32 |
Step 3: Find out which pair sums up to $\color{blue}{ b = -1 }$
| PRODUCT = -992 and SUM = -1 | |
| -1 992 | 1 -992 |
| -2 496 | 2 -496 |
| -4 248 | 4 -248 |
| -8 124 | 8 -124 |
| -16 62 | 16 -62 |
| -31 32 | 31 -32 |
Step 4: Put 31 and -32 into placeholders to get factored form.
$$ \begin{aligned} a^{2}-a-992 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ a^{2}-a-992 & = (x + 31)(x -32) \end{aligned} $$