Question
Factor polynomial $$ 9y^{2}-121x^{4} $$
Answer
$$ 9y^{2}-121x^{4} = (3y+11x^{2})(3y-11x^{2}) $$
Explanation
Rewrite $ 9y^2-121x^4 $ as:
$$ \color{blue}{ 9y^2-121x^4 = (3y)^2 - (11x^2)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 3y $ and $ II = 11x^2 $ , we have:
$$ 9y^2-121x^4 = (3y)^2 - (11x^2)^2 = ( 3y-11x^2 ) ( 3y+11x^2 ) $$This page was created using
Polynomial Factoring Calculator