Question
Factor polynomial $$ 9j^{3}+36j^{2}+4j+16 $$
Answer
$$ 9j^{3}+36j^{2}+4j+16 = ( 9j^{2}+4 )( j+4 ) $$
Explanation
To factor $ 9j^{3}+36j^{2}+4j+16 $ we can use factoring by grouping:
Group $ \color{blue}{ 9x^{3} }$ with $ \color{blue}{ 36x^{2} }$ and $ \color{red}{ 4x }$ with $ \color{red}{ 16 }$ then factor each group.
$$ \begin{aligned} 9j^{3}+36j^{2}+4j+16 = ( \color{blue}{ 9x^{3}+36x^{2} } ) + ( \color{red}{ 4x+16 }) &= \\ &= \color{blue}{ 9x^{2}( x+4 )} + \color{red}{ 4( x+4 ) } = \\ &= (9x^{2}+4)(x+4) \end{aligned} $$This page was created using
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