Question
Factor polynomial $$ -64x^{2}+9 $$
Answer
$$ -64x^{2}+9 = ( -8x+3 )( 8x+3 ) $$
Explanation
Rewrite $ -64x^{2}+9 $ as:
$$ -64x^{2}+9 = 9 -64x^2 = (3)^2 - (8x)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 3 $ and $ II = 8x $ , we have:
$$ -64x^{2}+9 = (3)^2 - (8x)^2 = ( -8x+3 ) ( 8x+3 ) $$This page was created using
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