Question
Factor polynomial $$ 8z^{4}-50z^{2} $$
Answer
$$ 8z^{4}-50z^{2} = 2z^{2}( 2z-5 )( 2z+5 ) $$
Explanation
Step 1 :
After factoring out $ 2z^{2} $ we have:
$$ 8z^{4}-50z^{2} = 2z^{2} ( 4z^{2}-25 ) $$Step 2 :
Rewrite $ 4z^{2}-25 $ as:
$$ 4z^{2}-25 = (2z)^2 - (5)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 2z $ and $ II = 5 $ , we have:
$$ 4z^{2}-25 = (2z)^2 - (5)^2 = ( 2z-5 ) ( 2z+5 ) $$This page was created using
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