Question
Factor polynomial $$ 8yz-6z-12y+9 $$
Answer
$$ 8yz-6z-12y+9 = (2z-3)(4y-3) $$
Explanation
To factor $ 8yz-6z-12y+9 $ we can use factoring by grouping.
Group $ \color{blue}{ 8yz }$ with $ \color{blue}{ -6z }$ and $ \color{red}{ -12y }$ with $ \color{red}{ 9 }$ then factor each group.
$$ \begin{aligned} 8yz-6z-12y+9 &= ( \color{blue}{ 8yz-6z } ) + ( \color{red}{ -12y+9 }) = \\ &= \color{blue}{ 2z( 4y-3 )} \color{red}{ -3( 4y-3 ) } = \\ &= (2z-3)(4y-3) \end{aligned} $$This page was created using
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