Step 1 :
Factor out common factor $ \color{blue}{ 8 } $:
$$ 8x^3+216y^3 = 8 ( x^3+27y^3 ) $$Step 2 :
To factor $ x^{3}+27y^{3} $ we can use sum of cubes formula:
$$ I^3 + II^3 = (I + II) (I^2 - I \cdot II + II^2)$$After putting $ I = x $ and $ II = 3y $ , we have:
$$ x^{3}+27y^{3} = ( x+3y ) ( x^{2}-3xy+9y^{2} ) $$