Question
Factor polynomial $$ 9y^{4}-6y^{3}-12y+8 $$
Answer
$$ 9y^{4}-6y^{3}-12y+8 = ( 3y^{3}-4 )( 3y-2 ) $$
Explanation
To factor $ 9y^{4}-6y^{3}-12y+8 $ we can use factoring by grouping:
Group $ \color{blue}{ 9x^{4} }$ with $ \color{blue}{ -6x^{3} }$ and $ \color{red}{ -12x }$ with $ \color{red}{ 8 }$ then factor each group.
$$ \begin{aligned} 9y^{4}-6y^{3}-12y+8 = ( \color{blue}{ 9x^{4}-6x^{3} } ) + ( \color{red}{ -12x+8 }) &= \\ &= \color{blue}{ 3x^{3}( 3x-2 )} + \color{red}{ -4( 3x-2 ) } = \\ &= (3x^{3}-4)(3x-2) \end{aligned} $$This page was created using
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