Question
Factor polynomial $$ 8ab-4a+6b-3 $$
Answer
$$ 8ab-4a+6b-3 = (4a+3)(2b-1) $$
Explanation
To factor $ 8ab-4a+6b-3 $ we can use factoring by grouping.
Group $ \color{blue}{ 8ab }$ with $ \color{blue}{ -4a }$ and $ \color{red}{ 6b }$ with $ \color{red}{ -3 }$ then factor each group.
$$ \begin{aligned} 8ab-4a+6b-3 &= ( \color{blue}{ 8ab-4a } ) + ( \color{red}{ 6b-3 }) = \\ &= \color{blue}{ 4a( 2b-1 )} + \color{red}{ 3( 2b-1 ) } = \\ &= (4a+3)(2b-1) \end{aligned} $$This page was created using
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