Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 8 }$ by the constant term $\color{blue}{c = -27} $.
$$ a \cdot c = -216 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -216 $ and add to $ b = 30 $.
Step 4: All pairs of numbers with a product of $ -216 $ are:
| PRODUCT = -216 | |
| -1 216 | 1 -216 |
| -2 108 | 2 -108 |
| -3 72 | 3 -72 |
| -4 54 | 4 -54 |
| -6 36 | 6 -36 |
| -8 27 | 8 -27 |
| -9 24 | 9 -24 |
| -12 18 | 12 -18 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 30 }$
| PRODUCT = -216 and SUM = 30 | |
| -1 216 | 1 -216 |
| -2 108 | 2 -108 |
| -3 72 | 3 -72 |
| -4 54 | 4 -54 |
| -6 36 | 6 -36 |
| -8 27 | 8 -27 |
| -9 24 | 9 -24 |
| -12 18 | 12 -18 |
Step 6: Replace middle term $ 30 x $ with $ 36x-6x $:
$$ 8x^{2}+30x-27 = 8x^{2}+36x-6x-27 $$Step 7: Apply factoring by grouping. Factor $ 4x $ out of the first two terms and $ -3 $ out of the last two terms.
$$ 8x^{2}+36x-6x-27 = 4x\left(2x+9\right) -3\left(2x+9\right) = \left(4x-3\right) \left(2x+9\right) $$