Question
Factor polynomial $$ 81x^{2}-64 $$
Answer
$$ 81x^{2}-64 = ( 9x-8 )( 9x+8 ) $$
Explanation
Rewrite $ 81x^{2}-64 $ as:
$$ 81x^{2}-64 = (9x)^2 - (8)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 9x $ and $ II = 8 $ , we have:
$$ 81x^{2}-64 = (9x)^2 - (8)^2 = ( 9x-8 ) ( 9x+8 ) $$This page was created using
Polynomial Factoring Calculator