Question
Factor polynomial $$ 81m^{4}-m^{2} $$
Answer
$$ 81m^{4}-m^{2} = m^{2}( 9m-1 )( 9m+1 ) $$
Explanation
Step 1 :
After factoring out $ m^{2} $ we have:
$$ 81m^{4}-m^{2} = m^{2} ( 81m^{2}-1 ) $$Step 2 :
Rewrite $ 81m^{2}-1 $ as:
$$ 81m^{2}-1 = (9m)^2 - (1)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 9m $ and $ II = 1 $ , we have:
$$ 81m^{2}-1 = (9m)^2 - (1)^2 = ( 9m-1 ) ( 9m+1 ) $$This page was created using
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