Question
Factor polynomial $$ 80h^{2}-5 $$
Answer
$$ 80h^{2}-5 = 5( 4h-1 )( 4h+1 ) $$
Explanation
Step 1 :
After factoring out $ 5 $ we have:
$$ 80h^{2}-5 = 5 ( 16h^{2}-1 ) $$Step 2 :
Rewrite $ 16h^{2}-1 $ as:
$$ 16h^{2}-1 = (4h)^2 - (1)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 4h $ and $ II = 1 $ , we have:
$$ 16h^{2}-1 = (4h)^2 - (1)^2 = ( 4h-1 ) ( 4h+1 ) $$This page was created using
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