Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 7 }$ by the constant term $\color{blue}{c = 8} $.
$$ a \cdot c = 56 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 56 $ and add to $ b = -18 $.
Step 4: All pairs of numbers with a product of $ 56 $ are:
| PRODUCT = 56 | |
| 1 56 | -1 -56 |
| 2 28 | -2 -28 |
| 4 14 | -4 -14 |
| 7 8 | -7 -8 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = -18 }$
| PRODUCT = 56 and SUM = -18 | |
| 1 56 | -1 -56 |
| 2 28 | -2 -28 |
| 4 14 | -4 -14 |
| 7 8 | -7 -8 |
Step 6: Replace middle term $ -18 x $ with $ -4x-14x $:
$$ 7x^{2}-18x+8 = 7x^{2}-4x-14x+8 $$Step 7: Apply factoring by grouping. Factor $ x $ out of the first two terms and $ -2 $ out of the last two terms.
$$ 7x^{2}-4x-14x+8 = x\left(7x-4\right) -2\left(7x-4\right) = \left(x-2\right) \left(7x-4\right) $$