It seems that $ 7x^{2}+16x+14 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 7 }$ by the constant term $\color{blue}{c = 14} $.
$$ a \cdot c = 98 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 98 $ and add to $ b = 16 $.
Step 4: All pairs of numbers with a product of $ 98 $ are:
| PRODUCT = 98 | |
| 1 98 | -1 -98 |
| 2 49 | -2 -49 |
| 7 14 | -7 -14 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 16 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 16 }$, we conclude the polynomial cannot be factored.