Step 1 :
After factoring out $ 3 $ we have:
$$ 75a^{2}-3 = 3 ( 25a^{2}-1 ) $$Step 2 :
Rewrite $ 25a^{2}-1 $ as:
$$ 25a^{2}-1 = (5a)^2 - (1)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 5a $ and $ II = 1 $ , we have:
$$ 25a^{2}-1 = (5a)^2 - (1)^2 = ( 5a-1 ) ( 5a+1 ) $$