Question
Factor polynomial $$ 6xz+3yz-8x-4y $$
Answer
$$ 6xz+3yz-8x-4y = (3z-4)(2x+y) $$
Explanation
To factor $ 6xz+3yz-8x-4y $ we can use factoring by grouping.
Group $ \color{blue}{ 6xz }$ with $ \color{blue}{ 3yz }$ and $ \color{red}{ -8x }$ with $ \color{red}{ -4y }$ then factor each group.
$$ \begin{aligned} 6xz+3yz-8x-4y &= ( \color{blue}{ 6xz+3yz } ) + ( \color{red}{ -8x-4y }) = \\ &= \color{blue}{ 3z( 2x+y )} \color{red}{ -4( 2x+y ) } = \\ &= (3z-4)(2x+y) \end{aligned} $$This page was created using
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