Question
Factor polynomial $$ 6m^{5}+42-am^{5}-7a $$
Answer
$$ 6m^{5}+42-am^{5}-7a = (6-a)(m^{5}+7) $$
Explanation
To factor $ 6m^5+42-am^5-7a $ we can use factoring by grouping.
Group $ \color{blue}{ 6m^5 }$ with $ \color{blue}{ 42 }$ and $ \color{red}{ -am^5 }$ with $ \color{red}{ -7a }$ then factor each group.
$$ \begin{aligned} 6m^5+42-am^5-7a &= ( \color{blue}{ 6m^5+42 } ) + ( \color{red}{ -am^5-7a }) = \\ &= \color{blue}{ 6( m^5+7 )} \color{red}{ -a( m^5+7 ) } = \\ &= (6-a)(m^5+7) \end{aligned} $$This page was created using
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