Question
Factor polynomial $$ 69p^{3}-46p^{2}+21p-14 $$
Answer
$$ 69p^{3}-46p^{2}+21p-14 = ( 23p^{2}+7 )( 3p-2 ) $$
Explanation
To factor $ 69p^{3}-46p^{2}+21p-14 $ we can use factoring by grouping:
Group $ \color{blue}{ 69x^{3} }$ with $ \color{blue}{ -46x^{2} }$ and $ \color{red}{ 21x }$ with $ \color{red}{ -14 }$ then factor each group.
$$ \begin{aligned} 69p^{3}-46p^{2}+21p-14 = ( \color{blue}{ 69x^{3}-46x^{2} } ) + ( \color{red}{ 21x-14 }) &= \\ &= \color{blue}{ 23x^{2}( 3x-2 )} + \color{red}{ 7( 3x-2 ) } = \\ &= (23x^{2}+7)(3x-2) \end{aligned} $$This page was created using
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