Step 1 :
After factoring out $ x $ we have:
$$ -25x^{3}+64x = x ( -25x^{2}+64 ) $$Step 2 :
Rewrite $ -25x^{2}+64 $ as:
$$ -25x^{2}+64 = 64 -25x^2 = (8)^2 - (5x)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 8 $ and $ II = 5x $ , we have:
$$ -25x^{2}+64 = (8)^2 - (5x)^2 = ( -5x+8 ) ( 5x+8 ) $$