Question
Factor polynomial $$ 64x^{6}-125y^{3} $$
Answer
$$ 64x^{6}-125y^{3} = (4x^{2}-5y)(16x^{4}+20x^{2}y+25y^{2}) $$
Explanation
To factor $ 64x^{6}-125y^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = 4x^2 $ and $ II = 5y $ , we have:
$$ 64x^{6}-125y^{3} = ( 4x^{2}-5y ) ( 16x^{4}+20x^{2}y+25y^{2} ) $$This page was created using
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