Question
Factor polynomial $$ 64c^{4}-121d^{6} $$
Answer
$$ 64c^{4}-121d^{6} = (8c^{2}+11d^{3})(8c^{2}-11d^{3}) $$
Explanation
Rewrite $ 64c^4-121d^6 $ as:
$$ \color{blue}{ 64c^4-121d^6 = (8c^2)^2 - (11d^3)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 8c^2 $ and $ II = 11d^3 $ , we have:
$$ 64c^4-121d^6 = (8c^2)^2 - (11d^3)^2 = ( 8c^2-11d^3 ) ( 8c^2+11d^3 ) $$This page was created using
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