To factor $ 5y^{3}-3y^{2}+15y-9 $ we can use factoring by grouping:
Group $ \color{blue}{ 5x^{3} }$ with $ \color{blue}{ -3x^{2} }$ and $ \color{red}{ 15x }$ with $ \color{red}{ -9 }$ then factor each group.
$$ \begin{aligned} 5y^{3}-3y^{2}+15y-9 = ( \color{blue}{ 5x^{3}-3x^{2} } ) + ( \color{red}{ 15x-9 }) &= \\ &= \color{blue}{ x^{2}( 5x-3 )} + \color{red}{ 3( 5x-3 ) } = \\ &= (x^{2}+3)(5x-3) \end{aligned} $$