Question
Factor polynomial $$ 5u^{2}-405 $$
Answer
$$ 5u^{2}-405 = 5( u-9 )( u+9 ) $$
Explanation
Step 1 :
After factoring out $ 5 $ we have:
$$ 5u^{2}-405 = 5 ( u^{2}-81 ) $$Step 2 :
Rewrite $ u^{2}-81 $ as:
$$ u^{2}-81 = (u)^2 - (9)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = u $ and $ II = 9 $ , we have:
$$ u^{2}-81 = (u)^2 - (9)^2 = ( u-9 ) ( u+9 ) $$This page was created using
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