Step 1 :
After factoring out $ 4x $ we have:
$$ 4x^{3}-220x^{2}+2800x = 4x ( x^{2}-55x+700 ) $$Step 2 :
Step 2: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = -55 } ~ \text{ and } ~ \color{red}{ c = 700 }$$Now we must discover two numbers that sum up to $ \color{blue}{ -55 } $ and multiply to $ \color{red}{ 700 } $.
Step 3: Find out pairs of numbers with a product of $\color{red}{ c = 700 }$.
| PRODUCT = 700 | |
| 1 700 | -1 -700 |
| 2 350 | -2 -350 |
| 4 175 | -4 -175 |
| 5 140 | -5 -140 |
| 7 100 | -7 -100 |
| 10 70 | -10 -70 |
| 14 50 | -14 -50 |
| 20 35 | -20 -35 |
| 25 28 | -25 -28 |
Step 4: Find out which pair sums up to $\color{blue}{ b = -55 }$
| PRODUCT = 700 and SUM = -55 | |
| 1 700 | -1 -700 |
| 2 350 | -2 -350 |
| 4 175 | -4 -175 |
| 5 140 | -5 -140 |
| 7 100 | -7 -100 |
| 10 70 | -10 -70 |
| 14 50 | -14 -50 |
| 20 35 | -20 -35 |
| 25 28 | -25 -28 |
Step 5: Put -20 and -35 into placeholders to get factored form.
$$ \begin{aligned} x^{2}-55x+700 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ x^{2}-55x+700 & = (x -20)(x -35) \end{aligned} $$