It seems that $ 4x^{2}+3x-12 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 4 }$ by the constant term $\color{blue}{c = -12} $.
$$ a \cdot c = -48 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -48 $ and add to $ b = 3 $.
Step 4: All pairs of numbers with a product of $ -48 $ are:
| PRODUCT = -48 | |
| -1 48 | 1 -48 |
| -2 24 | 2 -24 |
| -3 16 | 3 -16 |
| -4 12 | 4 -12 |
| -6 8 | 6 -8 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 3 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 3 }$, we conclude the polynomial cannot be factored.