Question
Factor polynomial $$ 4x^{2}+16xy-7x-28y $$
Answer
$$ 4x^{2}+16xy-7x-28y = (4x-7)(x+4y) $$
Explanation
To factor $ 4x^2+16xy-7x-28y $ we can use factoring by grouping.
Group $ \color{blue}{ 4x^2 }$ with $ \color{blue}{ 16xy }$ and $ \color{red}{ -7x }$ with $ \color{red}{ -28y }$ then factor each group.
$$ \begin{aligned} 4x^2+16xy-7x-28y &= ( \color{blue}{ 4x^2+16xy } ) + ( \color{red}{ -7x-28y }) = \\ &= \color{blue}{ 4x( x+4y )} \color{red}{ -7( x+4y ) } = \\ &= (4x-7)(x+4y) \end{aligned} $$This page was created using
Polynomial Factoring Calculator