Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 4 }$ by the constant term $\color{blue}{c = 375} $.
$$ a \cdot c = 1500 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 1500 $ and add to $ b = -115 $.
Step 4: All pairs of numbers with a product of $ 1500 $ are:
| PRODUCT = 1500 | |
| 1 1500 | -1 -1500 |
| 2 750 | -2 -750 |
| 3 500 | -3 -500 |
| 4 375 | -4 -375 |
| 5 300 | -5 -300 |
| 6 250 | -6 -250 |
| 10 150 | -10 -150 |
| 12 125 | -12 -125 |
| 15 100 | -15 -100 |
| 20 75 | -20 -75 |
| 25 60 | -25 -60 |
| 30 50 | -30 -50 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = -115 }$
| PRODUCT = 1500 and SUM = -115 | |
| 1 1500 | -1 -1500 |
| 2 750 | -2 -750 |
| 3 500 | -3 -500 |
| 4 375 | -4 -375 |
| 5 300 | -5 -300 |
| 6 250 | -6 -250 |
| 10 150 | -10 -150 |
| 12 125 | -12 -125 |
| 15 100 | -15 -100 |
| 20 75 | -20 -75 |
| 25 60 | -25 -60 |
| 30 50 | -30 -50 |
Step 6: Replace middle term $ -115 x $ with $ -15x-100x $:
$$ 4x^{2}-115x+375 = 4x^{2}-15x-100x+375 $$Step 7: Apply factoring by grouping. Factor $ x $ out of the first two terms and $ -25 $ out of the last two terms.
$$ 4x^{2}-15x-100x+375 = x\left(4x-15\right) -25\left(4x-15\right) = \left(x-25\right) \left(4x-15\right) $$