Question
Factor polynomial $$ 4w^{4}-64w^{2} $$
Answer
$$ 4w^{4}-64w^{2} = 4w^{2}( w-4 )( w+4 ) $$
Explanation
Step 1 :
After factoring out $ 4w^{2} $ we have:
$$ 4w^{4}-64w^{2} = 4w^{2} ( w^{2}-16 ) $$Step 2 :
Rewrite $ w^{2}-16 $ as:
$$ w^{2}-16 = (w)^2 - (4)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = w $ and $ II = 4 $ , we have:
$$ w^{2}-16 = (w)^2 - (4)^2 = ( w-4 ) ( w+4 ) $$This page was created using
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