Question
Factor polynomial $$ 49b^{4}-25t^{2} $$
Answer
$$ 49b^{4}-25t^{2} = (7b^{2}+5t)(7b^{2}-5t) $$
Explanation
Rewrite $ 49b^4-25t^2 $ as:
$$ \color{blue}{ 49b^4-25t^2 = (7b^2)^2 - (5t)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 7b^2 $ and $ II = 5t $ , we have:
$$ 49b^4-25t^2 = (7b^2)^2 - (5t)^2 = ( 7b^2-5t ) ( 7b^2+5t ) $$This page was created using
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