Question
Factor polynomial $$ -121p^{2}+49 $$
Answer
$$ -121p^{2}+49 = ( -11p+7 )( 11p+7 ) $$
Explanation
Rewrite $ -121p^{2}+49 $ as:
$$ -121p^{2}+49 = 49 -121x^2 = (7)^2 - (11p)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 7 $ and $ II = 11p $ , we have:
$$ -121p^{2}+49 = (7)^2 - (11p)^2 = ( -11p+7 ) ( 11p+7 ) $$This page was created using
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