It seems that $ 3x^{2}+12x-35 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 3 }$ by the constant term $\color{blue}{c = -35} $.
$$ a \cdot c = -105 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -105 $ and add to $ b = 12 $.
Step 4: All pairs of numbers with a product of $ -105 $ are:
| PRODUCT = -105 | |
| -1 105 | 1 -105 |
| -3 35 | 3 -35 |
| -5 21 | 5 -21 |
| -7 15 | 7 -15 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 12 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 12 }$, we conclude the polynomial cannot be factored.