It seems that $ 3x^{2}-7x-14 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 3 }$ by the constant term $\color{blue}{c = -14} $.
$$ a \cdot c = -42 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -42 $ and add to $ b = -7 $.
Step 4: All pairs of numbers with a product of $ -42 $ are:
| PRODUCT = -42 | |
| -1 42 | 1 -42 |
| -2 21 | 2 -21 |
| -3 14 | 3 -14 |
| -6 7 | 6 -7 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = -7 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ -7 }$, we conclude the polynomial cannot be factored.