Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 3 }$ by the constant term $\color{blue}{c = 450} $.
$$ a \cdot c = 1350 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 1350 $ and add to $ b = -145 $.
Step 4: All pairs of numbers with a product of $ 1350 $ are:
| PRODUCT = 1350 | |
| 1 1350 | -1 -1350 |
| 2 675 | -2 -675 |
| 3 450 | -3 -450 |
| 5 270 | -5 -270 |
| 6 225 | -6 -225 |
| 9 150 | -9 -150 |
| 10 135 | -10 -135 |
| 15 90 | -15 -90 |
| 18 75 | -18 -75 |
| 25 54 | -25 -54 |
| 27 50 | -27 -50 |
| 30 45 | -30 -45 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = -145 }$
| PRODUCT = 1350 and SUM = -145 | |
| 1 1350 | -1 -1350 |
| 2 675 | -2 -675 |
| 3 450 | -3 -450 |
| 5 270 | -5 -270 |
| 6 225 | -6 -225 |
| 9 150 | -9 -150 |
| 10 135 | -10 -135 |
| 15 90 | -15 -90 |
| 18 75 | -18 -75 |
| 25 54 | -25 -54 |
| 27 50 | -27 -50 |
| 30 45 | -30 -45 |
Step 6: Replace middle term $ -145 x $ with $ -10x-135x $:
$$ 3x^{2}-145x+450 = 3x^{2}-10x-135x+450 $$Step 7: Apply factoring by grouping. Factor $ x $ out of the first two terms and $ -45 $ out of the last two terms.
$$ 3x^{2}-10x-135x+450 = x\left(3x-10\right) -45\left(3x-10\right) = \left(x-45\right) \left(3x-10\right) $$