Question
Factor polynomial $$ 36y^{2}-z^{2} $$
Answer
$$ 36y^{2}-z^{2} = (6y+z)(6y-z) $$
Explanation
Rewrite $ 36y^2-z^2 $ as:
$$ \color{blue}{ 36y^2-z^2 = (6y)^2 - (z)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 6y $ and $ II = z $ , we have:
$$ 36y^2-z^2 = (6y)^2 - (z)^2 = ( 6y-z ) ( 6y+z ) $$This page was created using
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