Question
Factor polynomial $$ 36x^{18}-49y^{14} $$
Answer
$$ 36x^{18}-49y^{14} = (6x^{9}+7y^{7})(6x^{9}-7y^{7}) $$
Explanation
Rewrite $ 36x^18-49y^14 $ as:
$$ \color{blue}{ 36x^18-49y^14 = (6x^9)^2 - (7y^7)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 6x^9 $ and $ II = 7y^7 $ , we have:
$$ 36x^18-49y^14 = (6x^9)^2 - (7y^7)^2 = ( 6x^9-7y^7 ) ( 6x^9+7y^7 ) $$This page was created using
Polynomial Factoring Calculator