Question
Factor polynomial $$ 36s^{2}-121t^{2} $$
Answer
$$ 36s^{2}-121t^{2} = (6s+11t)(6s-11t) $$
Explanation
Rewrite $ 36s^2-121t^2 $ as:
$$ \color{blue}{ 36s^2-121t^2 = (6s)^2 - (11t)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 6s $ and $ II = 11t $ , we have:
$$ 36s^2-121t^2 = (6s)^2 - (11t)^2 = ( 6s-11t ) ( 6s+11t ) $$This page was created using
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