Question
Factor polynomial $$ 36j^{2}-100k^{6}m^{4} $$
Answer
$$ 36j^{2}-100k^{6}m^{4} = 4(3j+5k^{3}m^{2})(3j-5k^{3}m^{2}) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ 4 } $:
$$ 36j^2-100k^6m^4 = 4 ( 9j^2-25k^6m^4 ) $$Step 2 :
Rewrite $ 9j^2-25k^6m^4 $ as:
$$ \color{blue}{ 9j^2-25k^6m^4 = (3j)^2 - (5k^3m^2)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 3j $ and $ II = 5k^3m^2 $ , we have:
$$ 9j^2-25k^6m^4 = (3j)^2 - (5k^3m^2)^2 = ( 3j-5k^3m^2 ) ( 3j+5k^3m^2 ) $$This page was created using
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