Question
Factor polynomial $$ 36b^{2}-121u^{2} $$
Answer
$$ 36b^{2}-121u^{2} = (6b+11u)(6b-11u) $$
Explanation
Rewrite $ 36b^2-121u^2 $ as:
$$ \color{blue}{ 36b^2-121u^2 = (6b)^2 - (11u)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 6b $ and $ II = 11u $ , we have:
$$ 36b^2-121u^2 = (6b)^2 - (11u)^2 = ( 6b-11u ) ( 6b+11u ) $$This page was created using
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