Question
Factor polynomial $$ 343a^{3}-729b^{6} $$
Answer
$$ 343a^{3}-729b^{6} = (7a-9b^{2})(49a^{2}+63ab^{2}+81b^{4}) $$
Explanation
To factor $ 343a^{3}-729b^{6} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = 7a $ and $ II = 9b^2 $ , we have:
$$ 343a^{3}-729b^{6} = ( 7a-9b^{2} ) ( 49a^{2}+63ab^{2}+81b^{4} ) $$This page was created using
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