To factor $ 30x^{3}+40x^{2}+3x+4 $ we can use factoring by grouping:
Group $ \color{blue}{ 30x^{3} }$ with $ \color{blue}{ 40x^{2} }$ and $ \color{red}{ 3x }$ with $ \color{red}{ 4 }$ then factor each group.
$$ \begin{aligned} 30x^{3}+40x^{2}+3x+4 = ( \color{blue}{ 30x^{3}+40x^{2} } ) + ( \color{red}{ 3x+4 }) &= \\ &= \color{blue}{ 10x^{2}( 3x+4 )} + \color{red}{ 1( 3x+4 ) } = \\ &= (10x^{2}+1)(3x+4) \end{aligned} $$