Step 1 :
After factoring out $ -4 $ we have:
$$ -20r^{2}+12r+12 = -4 ( 5r^{2}-3r-3 ) $$Step 2 :
Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 3: Multiply the leading coefficient $\color{blue}{ a = 5 }$ by the constant term $\color{blue}{c = -3} $.
$$ a \cdot c = -15 $$Step 4: Find out two numbers that multiply to $ a \cdot c = -15 $ and add to $ b = -3 $.
Step 5: All pairs of numbers with a product of $ -15 $ are:
| PRODUCT = -15 | |
| -1 15 | 1 -15 |
| -3 5 | 3 -5 |
Step 6: Find out which factor pair sums up to $\color{blue}{ b = -3 }$
Step 7: Because none of these pairs will give us a sum of $ \color{blue}{ -3 }$, we conclude the polynomial cannot be factored.