Question
Factor polynomial $$ 2y^{3}-4y^{2}-3y+6 $$
Answer
$$ 2y^{3}-4y^{2}-3y+6 = ( 2y^{2}-3 )( y-2 ) $$
Explanation
To factor $ 2y^{3}-4y^{2}-3y+6 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ -4x^{2} }$ and $ \color{red}{ -3x }$ with $ \color{red}{ 6 }$ then factor each group.
$$ \begin{aligned} 2y^{3}-4y^{2}-3y+6 = ( \color{blue}{ 2x^{3}-4x^{2} } ) + ( \color{red}{ -3x+6 }) &= \\ &= \color{blue}{ 2x^{2}( x-2 )} + \color{red}{ -3( x-2 ) } = \\ &= (2x^{2}-3)(x-2) \end{aligned} $$This page was created using
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