To factor $ 2x^{3}-3x^{2}+8x-12 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ -3x^{2} }$ and $ \color{red}{ 8x }$ with $ \color{red}{ -12 }$ then factor each group.
$$ \begin{aligned} 2x^{3}-3x^{2}+8x-12 = ( \color{blue}{ 2x^{3}-3x^{2} } ) + ( \color{red}{ 8x-12 }) &= \\ &= \color{blue}{ x^{2}( 2x-3 )} + \color{red}{ 4( 2x-3 ) } = \\ &= (x^{2}+4)(2x-3) \end{aligned} $$