Step 1 :
Factor out common factor $ \color{blue}{ 2 } $:
$$ 2x^3-2c^3 = 2 ( x^3-c^3 ) $$Step 2 :
To factor $ x^{3}-c^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = x $ and $ II = c $ , we have:
$$ x^{3}-c^{3} = ( x-c ) ( x^{2}+cx+c^{2} ) $$