It seems that $ 2x^{2}+x-75 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 2 }$ by the constant term $\color{blue}{c = -75} $.
$$ a \cdot c = -150 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -150 $ and add to $ b = 1 $.
Step 4: All pairs of numbers with a product of $ -150 $ are:
| PRODUCT = -150 | |
| -1 150 | 1 -150 |
| -2 75 | 2 -75 |
| -3 50 | 3 -50 |
| -5 30 | 5 -30 |
| -6 25 | 6 -25 |
| -10 15 | 10 -15 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 1 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 1 }$, we conclude the polynomial cannot be factored.