Question
Factor polynomial $$ 2m^{3}-6m^{2}-3m+9 $$
Answer
$$ 2m^{3}-6m^{2}-3m+9 = ( 2m^{2}-3 )( m-3 ) $$
Explanation
To factor $ 2m^{3}-6m^{2}-3m+9 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ -6x^{2} }$ and $ \color{red}{ -3x }$ with $ \color{red}{ 9 }$ then factor each group.
$$ \begin{aligned} 2m^{3}-6m^{2}-3m+9 = ( \color{blue}{ 2x^{3}-6x^{2} } ) + ( \color{red}{ -3x+9 }) &= \\ &= \color{blue}{ 2x^{2}( x-3 )} + \color{red}{ -3( x-3 ) } = \\ &= (2x^{2}-3)(x-3) \end{aligned} $$This page was created using
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