Question
Factor polynomial $$ 2j^{2}k-2j^{2}+jk-j $$
Answer
$$ 2j^{2}k-2j^{2}+jk-j = j(2j+1)(k-1) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ j } $:
$$ 2j^2k-2j^2+jk-j = j ( 2jk-2j+k-1 ) $$Step 2 :
To factor $ 2jk-2j+k-1 $ we can use factoring by grouping.
Group $ \color{blue}{ 2jk }$ with $ \color{blue}{ -2j }$ and $ \color{red}{ k }$ with $ \color{red}{ -1 }$ then factor each group.
$$ \begin{aligned} 2jk-2j+k-1 &= ( \color{blue}{ 2jk-2j } ) + ( \color{red}{ k-1 }) = \\ &= \color{blue}{ 2j( k-1 )} + \color{red}{ 1( k-1 ) } = \\ &= (2j+1)(k-1) \end{aligned} $$This page was created using
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